1) Let us consider 3 points A, B, C be given points which are not present in straight line.
2) Draw lines connecting A with B, B with C.
3) Draw perpendicular bisectors to lines AB, BC
4) These two perpendicular bisectors intersect at point ‘O’
5) With O as centre and radious equal to OA, draw an arc passing through points A, B, C
Method 2:
Problem: To find the centre of an Arc
1. Draw an arc AB.
2. Draw a line (Chord) that connects the two points of the arc.
3. Set your compass more than half of the length of line and place compass on one end of the line ( or arc) and draw arc's above and below the arc AB.
4. Keeping the same distance set on your compass, swing arcs from another end of the line, draw arcs above and below the arc AB cutting previously drawn arc's.
5. Draw a line through the two intersection points of the arcs.
5. It will cut the line AB at 'O', This is the centre of the chord.
In Geometry, bisecting an arc is cutting arc exactly in half.
Problem: To bisect an Arc
1. Draw an arc AB.
In Geometry, Bisecting a line is cutting a line exactly in half. It may also be referred to as constructing a perpendicular bisector as the line you are drawing will be at a right angle to the original line. A line that passes through the mid point of the line segment is known as the segment Bisector.
Problem: To bisect a given straight line AB
1. Draw a straight line of given dimension and mark start and end points as A, B.
2. To bisect this line, set your compass to just more than half the length of the line. Keep your compass this size for the rest of the question.
5. Draw a straight line through where the two arcs intersect above and below the line (i.e., C,D). It will cut the line AB at O. CD bisects AB at right angles.
6. Measure both sides of the line from 'O' check that they are of equal length, if they are equal we did it correctly.
